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FB_MEMMOVE


Copies a block of memory from a location to another

Syntax

` declare function fb_memmove cdecl ( byref dst as any, byref src as any, byval bytes as uinteger ) as any ptr

`

Usage

` [result =] fb_memmove( dst, src, bytes )

`

Parameters

dst

starting address of destination memory

src

starting address of source memory

bytes

number of bytes to copy

Return Value

The starting address of destination memory is returned.

Description

fb_memmove copies a given number of bytes from the memory location src to the memory location dst. Each starting address is taken from a reference to a variable or array element.

Copying takes place as if an intermediate buffer were used, allowing the destination and source areas to overlap in any way (safer approach, and for any platform). Using fb_memcopy is sufficient (and may induce greater speed) when the memory areas do not overlap.

To avoid overflows, the valid memory areas pointed to by both src and dst must be at least equal in size to the number of bytes to be copied.

The underlying type of the objects pointed to by both the source and destination pointers are irrelevant for this function.

The function does not check for any terminating null character in the source area. It always copies exactly the given number of bytes.

The result is a binary copy of the data.

Note: In order to copy from/to memory referenced by a Pointer, it must be dereferenced first (or else specify in argument term the Byval keyword in front of the pointer name). Otherwise, fb_memmove will try to copy the bytes from/to the pointer variable's memory location.

Examples

start GeSHi

vb
Dim As ZString * 33 z = "memmove can be very useful......"

Print z

fb_memmove(z[20], z[15], 11)

Print z

Sleep

end GeSHi

Output:

memmove can be very useful......
memmove can be very very useful.

Version

  • Since fbc 1.08.0

Differences from QB

  • The behavior and usage is new to FreeBASIC.

See also

  • fb_memcopy
  • fb_memcopyclear

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