Operator +（加法）

• 来源: https://www.freebasic.net/wiki/wikka.php?wakka=KeyPgOpAdd
• 最后更新: 2019-07-04

---

对两个表达式求和。

语法

declare operator + ( byref lhs as integer, byref rhs as integer ) as integer
declare operator + ( byref lhs as uinteger, byref rhs as uinteger ) as uinteger

declare operator + ( byref lhs as single, byref rhs as single ) as single
declare operator + ( byref lhs as double, byref rhs as double ) as double

declare operator + ( byref lhs as T Pointer, byref rhs as integer ) as T Pointer
declare operator + ( byref rhs as integer, byref lhs as T Pointer ) as T Pointer

declare operator + ( byref lhs as T, byref rhs as integer ) as T
declare operator + ( byref lhs as integer, byref rhs as T ) as T

用法

result = lhs + rhs